Hi. I don’t understand what does the #define OUT do? Can someone explain? Thanks!
All it does is label an argument that you know the calling function will be editing the past variables.
It is simply the instructors desired style, I assume because he hails from C# which has a specifier of “out” to indicate that the passed reference is writable.
I didn’t like his solution, not required, only do it if you like it
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