Much more efficient way for n doors?

Hey community,
I am asking myself why we say that a door is constantly checking whether the actor is overlapping the “plate” instead of assigning the doors to one plate and opening them if the plate’s tick event recognizes the overlapping. If one plate is checking for overlapping it should be way more efficient than each door checking for it? n parallel checks for n door vs. 1 check for n doors. I hope my point is clear. Is it right that the second method is way more efficient?

Thanks in advance

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