My over-complicated method of placing pins

The goal of this scene was to make it as accurate as possible. There is probably a simpler way to place pins but this is what I ended up doing.

  1. I set the scaling in Blender to work in feet, since all of the research I did said that a lane is 60’ long and 42" wide.
  2. I converted the size of my pin and bowling ball to inches.
  3. I created a plane that matches the dimensions of a real lane (42"x60’).
  4. For the placement of the pins, I used this website as a reference.
  5. The article specifies that each pin must be 12" from their respective neighbors… so this was a new challenge.
    i. First of all I wanted to use the array modifier.
    ii. The array modifier uses a relative offset, so the width of the pin itself. So I had to convert 12" to pin units.
    iii. My pin was 4.665" in (maximum) width, so 12" ended up being 2.572 pins.
    iv. I started with the head pin, meaning that the other pins will be 12" away, but at a 30 degree angle. So I had to use some trig.
    v. To find the offset directly behind the pin, I used the expression d*cos(30). For the offset to the left and right of the pin I used the expression d*sin(30). d in this case is the distance between the two pins, so for me it was 12" or 2.572 pins (because the array modifier uses a relative offset).
    vi. So in the end, I put 2.572*cos(pi/6) into the x offset field, and 2.572*sin(pi/6) for the y offset field.

Here’s a diagram:

Here’s a render:

Here’s a render from the bowler’s perspective:

2 Likes

That ball looks puzzled? Math is not his / her strongest skill? :wink: JK. Good job with the maths and models too :slight_smile:

Cheers, Jax