IsIsogram() function

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This is my solution, fresh from the keyboard and still steaming :slight_smile:

TMap<char, bool> LetterSeen;	// setup map
for (auto Letter : Word)		//	loop through provided word
{
	Letter = tolower(Letter);
	if (LetterSeen[Letter])		// if the letter is in the map
	{
		return false;			// we do NOT have an isogram
	}
	else	// otherwise
	{
		LetterSeen[Letter] = true;			// add the letter to the map as seen
	}
}
return true; // for example in cases where /0 is entered